>> mp(1/3) % Accuracy is limited to double precision ans = % since 1/3 was evaluated in double precision first 0.33333333333333331482961625624739099293947219848633
How are the extended digits, i.e. 1482961625624739099293947219848633, created? Are they totally random numbers or some of them are determined by the guard digits in the double-precision representation of 1/3?
I've been thinking that a natural extension would be done by trailing zeros, resulting, for example, in the example above, something like:
Any discussion/comment is welcome. Thanks!
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